C++ Program to find the cube of a number using void pointer

This program finds the cube of a number in C++. The number is read as input and is stored is the variable n. The program uses a void pointer which points to n.  The statement int *pint= (int *)p; stores the value at p to the pointer variable pint. Then the program repeatedly multiples pint 3 times which gives the cube of the given number.

Program

#include<iostream.h>



#include<conio.h>



void main()



{



          int n;



          void *p;



          p=&n;



          cout<<"Enter the number";



          cin>>n;



          int *pint= (int *)p;



          n=(*pint)*(*pint)*(*pint);



          cout<<"Cube of the number is\n";



          cout<<n;



          getch();



}